

Harsh Ananth's profile, qualifications and contact details have been verified by our experts
Harsh Ananth
- Rate RM4
- Response 1h

RM4/h
This tutor is currently unavailable
- Hindi
I can give best methodology for solving mathematics problems of both 1st and 2nd pu students
- Hindi
Lesson location
Recommended
Harsh Ananth is a respected tutor in our community. They are highly recommended for their commitment and the quality of their lessons. An excellent choice to progress with confidence.
About Harsh Ananth
I am Harsh studying Engineering now . I have a good knowledge in mathematics and Hindi. I can convenience the student as much as easier way . I have some tricky methods to solve maths in easier way for pu students at the end of extent . I too scored good marks in pu board examination by these methods itself.
About the lesson
- Primary
- Secondary
- SPM
- +6
levels :
Primary
Secondary
SPM
Form 6
STPM
Other
Beginner
Advanced
Kids
- English
All languages in which the lesson is available :
English
If you are getting less Mark's or maths is becoming hard to you
I have best methodology and easier method to solve and convenience you the subject
I will handle both maths and hindi
In online mode. I have experienceof teaching both subject for SSLC students
Recommendations
Recommendations come from relatives, friends and acquaintances of the teacher
The explaination level is too good so refer him
Hi is great in hindi teaching I think he will bee the good teacher and he has more skills
Hi is topper of hindi in school wise
He can make students to be perfect in that respective subjectHe will likewise direct you where we are slacking, our qualities... ,He explains difficult concepts in a simple manner,He focuses more on understanding than rote learning, thus sparking interest of the child in the subject
He teaches good concepts in the easier way .
Harsh was a very kind person and he solves problem very well and teaches life lessons nicely..
View more recommendations
Rates
Rate
- RM4
Pack rates
- 5h: RM21
- 10h: RM42
online
- RM4/h
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