Kayode - Maths tutor - Port Harcourt
1st lesson belanja
Kayode - Maths tutor - Port Harcourt

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Kayode

  • Rate RM15
  • Response 24h
  • Students

    Number of students accompanied by Kayode since their arrival at Superprof

    1

    Number of students accompanied by Kayode since their arrival at Superprof

Kayode - Maths tutor - Port Harcourt
  • 5 (2 reviews)

RM15/h

1st lesson belanja

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1st lesson belanja

1st lesson belanja

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

A dynamic and proficient Math tutor, incorporating sound knowledge of Engineering and Science to solving your mathematical problems. I teach the "understanding" of Math to aid your strength in not j

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

Lesson location

Recommended

Kayode is a respected tutor in our community. They are highly recommended for their commitment and the quality of their lessons. An excellent choice to progress with confidence.

About Kayode

I am a Civil Engineer but I've been passionate about teaching. I presently take home lessons and online tutorials in some other platforms. I engage the teaching of basic principle of mathematics and engineering to expose students to the concept behind each Mathematical problem and hence stir up your interest in not just the questions but the topic as a whole. Once you get the understanding of Mathematics, you can easily solve any question even beyond the scope of the particular question.

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About the lesson

  • Primary
  • Secondary
  • SPM
  • +8
  • levels :

    Primary

    Secondary

    SPM

    Form 6

    STPM

    Adult education

    Bachelor

    Masters

    Diploma

    Doctorate

    Matriculation

  • English

All languages in which the lesson is available :

English

Find the largest of three consecutive odd numbers whose sum is 57. Solution: Let the largest be x Consecutive odd numbers increase/decrease by difference of 2. This implies, other two numbers are (x-2) and (x-4) So, the sum; x + (x-2) + (x-4) = 57 Hence, solving, we have; 3x - 6= 57 Add 6 to both sides, 3x = 63 Dividing both sides by 3 X = 21. This implies that, the largest number is 21. Other two numbers are; X-2 => 21-2 = 19 X-4 => 21-4 = 17 Check: The sum = 21+19+17= 57

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Rates

Rate

  • RM15

Pack rates

  • 5h: RM75
  • 10h: RM150

free lessons

This first lesson is free to allow you to get to know your teacher so that they can best meet your needs.

  • 30mins

online

  • RM-2/h

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