

Universal
- Rate RM62
- Response 1h

RM62/h
1st lesson belanja
- Maths
About Universal
We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: π(π heads in π tosses)=(ππ)β ππβ ππβπ Plugging in the values: π(2 heads in 3 tosses)=(32)β (0.5)2β (0.5)1=3β 0.25β 0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.
About the lesson
- Primary
- Secondary
- SPM
- +8
levels :
Primary
Secondary
SPM
Form 6
STPM
Adult education
Bachelor
Masters
Diploma
Doctorate
Other
- English
All languages in which the lesson is available :
English
The probability of getting exactly \(2\) heads in \(3\) coin tosses is \(0.375\). We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: π(π heads in π tosses)=(ππ)β ππβ ππβπ Plugging in the values: π(2 heads in 3 tosses)=(32)β (0.5)2β (0.5)1=3β 0.25β 0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.
Rates
Rate
- RM62
Pack rates
- 5h: RM310
- 10h: RM620
online
- RM62/h
free lessons
This first lesson is free to allow you to get to know your teacher so that they can best meet your needs.
- 1hr
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